If a ray OC stands on line AB such that ∆ AOC =∆COB show that ∆A

1.	If a ray OC stands on line AB such that ∆ AOC =∆COB show that ∆AOC =90°
Answer» Here, AB is a straight line and ray OC stands on line AB, such that\xa0{tex}\\Delta AOC \\cong \\Delta COB.{/tex}By c.p.c.t,\xa0{tex}\\angle AOC=\\angle COB{/tex}Now,\xa0{tex}\\angle AOC+\\angle COB=180^{\\circ} (\\because \\text {linear pair}){/tex}{tex}\\Rightarrow \\angle AOC + \\angle AOC = 180^{\\circ}{/tex}{tex}\\Rightarrow 2\\angle AOC=180^{\\circ}{/tex}{tex}\\Rightarrow\\angle AOC = \\cfrac{180^{\\circ}}{2}{/tex}{tex}\\Rightarrow \\angle AOC = 90^ {\\circ}{/tex}Proved

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