1.

If a simple harmonic motion is represented by `(d^(2)x)/(dt^(2)) + alphax = 0`, its time period is :A. `2pialpha`B. `2pisqrt(alpha`C. `(2pi)/(alpha)`D. `(2pi)/(sqrt(alpha))`

Answer» Correct Answer - D
Comparing it with the standard equation of
S.H.M. `(d^(2)x)/(dt^(2))=-omega^(2)x`
We get, `omega^(2)=alpha`
`therefore omega=sqrt(alpha)`
`T=(2pi)/(omega)=(2pi)/(sqrt(alpha))`


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