1.

If a simple harmonic oscillator has got a displacement of 0.02m and acceleration eaual to 2.0 m"/"s^(2) at any time, the angular frequency of the oscillator is equal to…….

Answer»

`10 rad"/"s`
`0.1 rad"/"s`
`100 rad"/"s`
`1 rad"/"s`

Solution :`OMEGA =SQRT(("ACCELERATION")/("DISPLACEMENT"))`
`omega = sqrt((2.0)/(0.02))= 10 rad"/"s`.


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