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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2s, then its maximum velocity is……….. |
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Answer» `0.10 m"/"s` `AXX (2pi)/(T)= (50 xx 10^(-3))xx (2pi)/(2)` `=50xx 10^(-3)xx 3.14` `=150.7xx 10^(-3)` `approx 0.15 m"/"s`. |
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