1.

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2s, then its maximum velocity is………..

Answer»

`0.10 m"/"s`
`0.15 m"/"s`
`0.8 m"/"s`
`0.26 m"/"s`

SOLUTION :`v_("MAX")= A OMEGA`
`AXX (2pi)/(T)= (50 xx 10^(-3))xx (2pi)/(2)`
`=50xx 10^(-3)xx 3.14`
`=150.7xx 10^(-3)`
`approx 0.15 m"/"s`.


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