1.

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity isA. `0.10 m//s`B. `0.16 m//s`C. `0.25 m//s`D. `0.5 m//s`

Answer» Correct Answer - B
`v_(m)=Aomega`
`=50xx10^(-3)xx(2pi)/(2)`
`=50xx10^(-3)xx3.14-15.700xx10^(-2)`
`=0.157m//s`
`~~0.16m//s`


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