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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity isA. `0.10 m//s`B. `0.16 m//s`C. `0.25 m//s`D. `0.5 m//s` |
Answer» Correct Answer - B `v_(m)=Aomega` `=50xx10^(-3)xx(2pi)/(2)` `=50xx10^(-3)xx3.14-15.700xx10^(-2)` `=0.157m//s` `~~0.16m//s` |
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