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If \( A \sin \theta=3 \) and \( A \cos \theta=4 \) then ' \( \theta \) ' will be- |
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Answer» Given that \(Asinθ = 3\) ⇒ \(sinθ = 3/A\) ... (1) Also, \(Acosθ = 4\) ⇒ \(cosθ = 4/A\) ... (2) Squaring (1) and (2), and adding them both we get \(sin^2θ + cos^2θ = \frac{9}{A^2} + \frac{16}{A^2} = \frac{25}{A^2}\) ⇒ \(1 = \frac{25}{A^2}\) ⇒ \(A = 5\) Putting Value of \(A\) in (1), we get \(sinθ = \frac{3}{5} \) ⇒ \(θ = 37°\) |
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