1.

If a=sin4(3π2−α)+sin4(3π+α) and b=sin6(π2+α)+sin6(5π−α), then the value of 3a−2b is

Answer»

If a=sin4(3π2α)+sin4(3π+α) and b=sin6(π2+α)+sin6(5πα), then the value of 3a2b is



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