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If a soap bubble of radius 3 cm coalesce in vacuum under isothermal conditions with another soap bubble of radius 4 cm find the radius of the big soap bubble so formed. |
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Answer» SOLUTION :`r_(1)=3cm, r_(2)=4CM` Let R be the radius of the big drop Surface energy of big drop = Surface energy of first drop + Surface energy of second drop `THEREFORE 8piR^(2)S=(8pir_(1)^(2)+8pir_(2)^(2))S` `R=sqrt(r_(1)^(2)+r_(2)^(2))=sqrt(3^(2)+4^(2))=5CM` |
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