1.

If a soap bubble of radius 3 cm coalesce in vacuum under isothermal conditions with another soap bubble of radius 4 cm find the radius of the big soap bubble so formed.

Answer»

SOLUTION :`r_(1)=3cm, r_(2)=4CM`
Let R be the radius of the big drop
Surface energy of big drop = Surface energy of first drop + Surface energy of second drop
`THEREFORE 8piR^(2)S=(8pir_(1)^(2)+8pir_(2)^(2))S`
`R=sqrt(r_(1)^(2)+r_(2)^(2))=sqrt(3^(2)+4^(2))=5CM`


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