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If a source of sound approaches a stationery observer with velocity v then he observes an increase in frequency equal to `Deltan_(1)` if source recedes away from the stationary observer with same velocity v then he observer a decrease in frequency equal to `Deltan_(2)` then:A. `Deltan_(1)=Deltan_(2)`B. `Deltan_(1)geDeltan_(2)`C. `Deltan_(1)leDeltan_(2)`D. `Deltan_(1)geDeltan_(2) or Deltan_(2)geDeltan_(1)` depending upon velocity v |
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Answer» Correct Answer - B `Deltan_(1)="f"_(0) (v)/(v-v_(s)) - f_(0)=(v_(s)f_(0))/(v-v_(s))` `Deltan_(2)=f_(0)-"f"_(0) (v)/(v+v_(s)) = (v_(s)f_(0))/(v+v_(s))` clearly `Deltan_(1)geDeltan_(2)` |
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