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If a spring extends by X on loading,then the energy stored by the spring is (if T is tension in the spring and k is spring constant) |
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Answer» Energy stored = 1/2 × F × x .......(1) also in terms of spring constant F = k ∙ x hence x = (F/k) hence from (1), Energy = (1/2) × F × (F/k) = (F2 / 2k) Here F = Tension in the spring hence F = T ∴ Energy = [T2 / 2k] |
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