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If a stone is to hit at a point which is at a distance `d` away and at a height `h` (see fig) above the point from where the stone starts,then what is the value of initial speed `u` if the stone is launched at an angle `theta`? A. `d/sinthetasqrt(g/(2(d tan theta-h))`B. `d/costhetasqrt(g/(2(d tan theta-h))`C. `sqrt((gd)/(h cos ^(2)theta)`D. `sqrt((gd)/((d-h))` |
Answer» Correct Answer - B `h=(u sin theta)t-1/2"gt"^(2),d=(u cos theta)t` |
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