If a stone tied at the one end of a string of length 0.5 m is whirled in a horizontal circle with a constant speed 6 ms^(-1),then the acceleration of the stone is

If a stone tied at the one end of a string of length 0.5 m is whirled

1.	If a stone tied at the one end of a string of length 0.5 m is whirled in a horizontal circle with a constant speed 6 ms^(-1),then the acceleration of the stone is
Answer» `12 ms^(-2)` `36 ms^(-2)` `2pi^2 ms^(-2)` `72 ms^(-2)` Solution :Centripital acceleration ` =(v^2)/(R ) = (6^2)/(0.5)= (36)/(0.5) =72 ms^(-2)`