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If a stone tied at the one end of a string of length 0.5 m is whirled in a horizontal circle with a constant speed 6 ms-1 then the acceleration of the shone is –(a) 12 ms-2 (b) 36 ms-2 (c) 2π ms-2 (d) 72 ms-2 |
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Answer» (d) 72 ms-2 Centripetal acceleration = \(\frac{v ^2}{r}\) = \(\frac{6^2}{0.5}\)= \(\frac{36}{0.5}\) =72 ms-2 |
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