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If a variable frequency ac source is connected to a capacitor then with decrease in frequency the displacement current willA. increaseB. decreaseC. remains constantD. first decrease then increase |
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Answer» Correct Answer - B Current through capacitor, `I=(E)/(X_(C))=(E)/((1)/(omegaC))=omegaCE=2piupsilonCEor Ipropupsilon.` `therefore` decrease in frequency `upsilon` of ac source decreases the conduction current. As displacement current is equal to conduction current, decrease in `upsilon` decreases displacement current in circuit. |
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