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If a vector vecr is equall inclined with the vectors veca=costhetahati+sinthetahatj, vecb=-sinthetahati+costhetahatj and vecc=hatk, then the angle between vecr and veca is |
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Answer» `cos^(-1)(1/sqrt(2))` `vecb=-sinthetahati+costhetahatj` and `vecc=hatk` `|veca|=|vecb|=|vecc|` and `veca.vecb=vecb.vecc=vecc.veca` `therefore` Required angle is `cos^(-1)(1/sqrt(3))` |
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