1.

If a vector vecr is equall inclined with the vectors veca=costhetahati+sinthetahatj, vecb=-sinthetahati+costhetahatj and vecc=hatk, then the angle between vecr and veca is

Answer»

`cos^(-1)(1/sqrt(2))`
`cos^(-1)(1/sqrt(3))`
`cos^(-1)(1/3)`
`cos^(-1)(1/2)`

SOLUTION :`veca=costhetahati+sinthetahatj`
`vecb=-sinthetahati+costhetahatj`
and `vecc=hatk`
`|veca|=|vecb|=|vecc|` and `veca.vecb=vecb.vecc=vecc.veca`
`therefore` Required angle is `cos^(-1)(1/sqrt(3))`


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