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If `A xx(BxxC)=Bxx(CxxA)` and [ABC] = 0, then `A xx(BxxC)` is equal to |
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Answer» Correct Answer - A `because Axx(BxxC)=Bxx(CxxA)` `rArr (A.C)B-(A.B)C=(B.A)C-B.C)A` `rArr (B.C)A+(A.C)B-(A.B+B.A)C=0` `therefore B.C=0,A.C=0,A.B=0` `rArr B bot C,A bot C,A bot B ` `Axx(BxxC)=(A.C)B-(A.B)C=(0)B-(0)C=0` |
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