If a1,a2,a3,⋯⋯a2n are in A.P. and all terms of the A.P. are positive. The value of the series a1+a2n√a1+√a2+a2+a2n−1√a2+√a3+⋯⋯+an+an+1√an+√an+1=k(a1+a2n)√a1+√an+1, then 2kn is equal to

If a1,a2,a3,⋯⋯a2n are in A.P. and all terms of the A.P. are positi

1.	If a1,a2,a3,⋯⋯a2n are in A.P. and all terms of the A.P. are positive. The value of the series a1+a2n√a1+√a2+a2+a2n−1√a2+√a3+⋯⋯+an+an+1√an+√an+1=k(a1+a2n)√a1+√an+1, then 2kn is equal to
Answer» If $a_{1}, a_{2}, a_{3}, \dots \dots a_{2 n}$ are in $A . P .$ and all terms of the $A . P .$ are positive. The value of the series $\frac{a_{1} + a_{2 n}}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{a_{2} + a_{2 n - 1}}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \dots \dots + \frac{a_{n} + a_{n + 1}}{\sqrt{a_{n}} + \sqrt{a_{n + 1}}} = \frac{k (a_{1} + a_{2 n})}{\sqrt{a_{1}} + \sqrt{a_{n + 1}}}$ , then $\frac{2 k}{n}$ is equal to