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If , a2+b=2, then maximum value of the term independent of x in the expansion of (ax1/6+bx−1/3)9 is (a>0,b>0) |
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Answer» If , a2+b=2, then maximum value of the term independent of x in the expansion of (ax1/6+bx−1/3)9 is (a>0,b>0) |
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