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If A679B is a five digit number is divisible by 72 find ‘A’ and ‘B'? |
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Answer» If A679B is divisible by 72 then it should be divisible by 8 and 9. [ ∵ 8, 9 are the factors of 72] A679B is divisible by 9 then A + 6 + 7 + 9 + B = A + B + 22 = 27 (9 x 3) =A + B = 5………. (1) A679B → 79B/8 [From B (2,4,6,8) we take B = 2] = 792/8 (R = 0) ∴ B = 2 From (1) ⇒ A + 2 = 5 ∴ A = 3, B = 2 |
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