1.

If A679B is a five digit number is divisible by 72 find ‘A’ and ‘B'?

Answer»

If A679B is divisible by 72 then it should be divisible by 8 and 9.

[ ∵ 8, 9 are the factors of 72]

A679B is divisible by 9 then

A + 6 + 7 + 9 + B = A + B + 22 = 27 (9 x 3)

=A + B = 5………. (1)

A679B → 79B/8 [From B (2,4,6,8) we take B = 2]

= 792/8 (R = 0)

∴ B = 2

From (1) ⇒ A + 2 = 5

∴ A = 3, B = 2



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