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If AA h in R - {0}, two distinct tangents can be drawn from the points (2+h,3h-1) to the curve y=x^(3)-6x^(2) - a+ bx then (a)/(b) is equal to "_____"

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SOLUTION :`y''=0impliesx=2`
Let `P` be the POINT of inflection
So `P-=(2,2b-a-16)`
Equation of tangent line passing through inflection
Point: `y=(b-12)x-a+8`…….(1)
Let `Q-=(2+h,3h-1)`
Locus of `Q:3x-y=7`…….(2)
From equation (1) and (2) we GET !
So, `a=15` adn `b=15`


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