1.

If AB × BA  = BCB, where A, B and C stand for just one digit and A ≠ B ≠ C, then the value of A + B + C is1. 62. 103. 94. 8

Answer» Correct Answer - Option 4 : 8

Given : 

AB × BA = BCB and A ≠ B ≠ C

Calculation

A and B cannot take the same value as A ≠ B

So, let A = 1 and B = 2

Then, AB × BA = 12 × 21 = 252

⇒ BCB = 252 

∴ C = 5 

A = 1, B = 2 and C = 5

∴ A + B + C = 1 + 2 + 5 = 8



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