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If ABC is an isosceles triangle and D is a point of BC such that AD ⊥ BC, then(a) AB2 − AD2 = BD.DC(b) AB2 − AD2 = BD2 − DC2(c) AB2 + AD2 = BD.DC(d) AB2 + AD2 = BD2 − DC2 |
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Answer» If ABC is an isosceles triangle and D is a point of BC such that AD ⊥ BC, then (a) AB2 − AD2 = BD.DC (b) AB2 − AD2 = BD2 − DC2 (c) AB2 + AD2 = BD.DC (d) AB2 + AD2 = BD2 − DC2 |
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