If ABCD is a parallelogram then prove that ar(∆ABD)=ar(∆BCD)=ar(∆ABC)=ar(∆ACD)=1/2ar(||gram ABCD)

If ABCD is a parallelogram then prove that ar(∆ABD)=ar(∆BCD)=ar(�

1.	If ABCD is a parallelogram then prove that ar(∆ABD)=ar(∆BCD)=ar(∆ABC)=ar(∆ACD)=1/2ar(\|\|gram ABCD)
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