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| 1. |
If ABCD is a rombus whose diagonals cut at the origin O, then OA + OB + OC + OD equals to |
| Answer» Solution : since, the diagonals of a rhombus bisect each other OA = - OC and OB =- OD OA + OB +OC + OD = - OC - OD + OC + OD = 0 | |