1.

If ABCDEF is a regular hexagon with AB = a and BC = b, then CE equals

Answer»

b - a
`- b`
b - 2a
None of these

Solution :In `DELTAABC, AB + BC = AC`
IMPLIES AC = a + b
AD is PARALLEL to BC and AD = 2BC

`therefore AD = 2b`
In `DeltaACD`, AC + CD = AD
`implies CD=2b-(a+b)=b-a`
Now, `CE = CD + DE = (b-a)-a=b-2a`


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