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If ABCDEF is a regular hexagon with AB = a and BC = b, then CE equals |
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Answer» b - a IMPLIES AC = a + b AD is PARALLEL to BC and AD = 2BC `therefore AD = 2b` In `DeltaACD`, AC + CD = AD `implies CD=2b-(a+b)=b-a` Now, `CE = CD + DE = (b-a)-a=b-2a` |
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