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if accidentily the calorimeter remained open to atmosphere for same time during the experiment due to which the steady state temperature comes out to be `30^(@)C` then total heat loss to surrounding during the experiment is (Use the specific heat capacity of the liquid from previous question) (A) `20 kcal` (B) `15kcal` (C) `10kcal` (D) `8kcal` . |
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Answer» Heat given by the sphere `= (1000) (1//2) (80-30) = 25,000cal` Heat absorbed by the water calorimeter system `= (9000 (1) (40 -30) + (200) (1//2) (40 -30)` `10,000cal` So heat loss to surrounding `= 15,000 cal` . |
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