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If acos3α+3acosαsin2α = m and asin3α+3acos2αsinα = n, Then (m+n)23+(m−n)23 is equal to |
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Answer» If acos3α+3acosαsin2α = m and asin3α+3acos2αsinα = n, Then (m+n)23+(m−n)23 is equal to |
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