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If AD,BE and CF are the altitudes of a triangle ABC whose vertex A is the point (-4,5). The coordinates of the points E and F are (4,1) and (-1,-4) respectively, then equation of BC is |
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Answer» `3X - 4y - 28 = 0` Slope of `AF = (5-(-4))/(-4+1) = (9)/(-3) =- 3` `:.` Slope of `CF = (1)/(3)` `:.` EQUATION of CF is `x - 3y - 11 = 0` (i) Slope of `AF =(5-1)/(-4-1) = (4)/(-8) =- (1)/(2)` `:.` Slope of `BE = 2` `:.` Equation of BE is `2x - y - 7 = 0`(ii) Solving (i) and (ii), we get point `O =(2,-3)` Equation of AC is `x+2y - 6 = 0` (iii) Solving (i) and (iii) we get point `C (8,-1)` Also slope of AO is `-4//3` `:.` Slope of BC is `3//4` `:.` Equation of BC is `3x - 4y - 28 = 0` |
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