1.

If `alpha=0.98` and current through emitter `i_(e)=20 mA`, the value of `beta` isA. 4.9B. 49C. 96D. 9.6

Answer» Correct Answer - B
`alpha = (I_(C))/(I_(E)) rArr I_(C) = alpha I_(E)`
`I_(B) = I_(E) - I_(C)`
`beta = (I_(C))/(I_(B))`


Discussion

No Comment Found

Related InterviewSolutions