Saved Bookmarks
| 1. |
If `alpha=0.98` and current through emitter `i_(e)=20 mA`, the value of `beta` isA. 4.9B. 49C. 96D. 9.6 |
|
Answer» Correct Answer - B `alpha = (I_(C))/(I_(E)) rArr I_(C) = alpha I_(E)` `I_(B) = I_(E) - I_(C)` `beta = (I_(C))/(I_(B))` |
|