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If alpha and beta are roots of equation 3/4"sin"((theta)/9)=sin^(3)theta+3sin^(3)((theta)/3)+9sin^(3)((theta)/9)+1/(4sqrt(2)) for 0lt theta lt (pi)/2, then tanalpha+tanbeta is equal to |
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Answer» `2+SQRT(3)` `IMPLIES sin 3theta=1/(sqrt(2))="sin"(pi)/4` or `"sin"(3pi)/4` `implies theta=(pi)/12` or `(pi)/4` `:."tan"(pi)/12=2-sqrt(3)`or `"tan"(pi)/4=1` `:."tan"(pi)/12+"tan"(pi)/4=3-sqrt(3)` |
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