1.

If alpha and beta are the eccentric angles of the ends of a focal chord of the ellipse then cos^(2)((alpha+beta)/(2))sec^(2)((alpha-beta)/(2))=

Answer»

`(a^(2)+B^(2))/(a^(2))`
`(a^(2)-b^(2))/(a^(2))`
`(a^(2))/(a^(2)+b^(2))`
`(a^(2))/(a^(2)-b^(2))`

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