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If (alpha, beta) are the roots of the equation 15 x ^(2) - 22 x + 8=0 and (alpha', beta') are the roots of the equation 8x^(2) - 22x + 15=0, then the equation of the circle on A (alpha, alpha') and B (beta, beta') as diameter is |
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Answer» `120 (x ^(2) + y ^(2)) - 22 ( 8X + 15y) + 289 =0` |
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