1.

If alpha+beta+gamma=2 theta then cos theta+cos(theta-alpha)+cos (theta-beta)+cos(theta-gamma)=

Answer»

`4"SIN"(alpha)/2."COS"(beta)/2."sin"(GAMMA)/2`
`4"cos"(alpha)/2."cos"(beta)/2."cos"(gamma)/2`
`4"sin"(alpha)/2."sin"(beta)/2"sin"(gamma)/2`
`4SIN alpha.sin beta.singamma`

Answer :B


Discussion

No Comment Found

Related InterviewSolutions