InterviewSolution
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InterviewSolution
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If `alpha` is a root of `x^4 = 1` with negative principal argument then the principal argument of `Delta(alpha) = |(1,1,1), (alpha^n, alpha^(n+1), alpha^(n+3)), (1/alpha^(n+1), 1/alpha^n, 0)|` isA. `(5pi)/(14)`B. `-(3pi)/(4)`C. `(pi)/(4)`D. `-(pi)/(4)` |
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Answer» Correct Answer - B `(b)` Clearly `alpha=-i` where `i^(2)=-1` So `Delta(alpha)=0+alpha^(2)+1-1-0-alpha^(3)` `=(-i)^(2)+1-1-(-i)^(3)` =-1+1-1-i=-1-i` So, principal argument of `Delta(alpha)` is `-(3pi)/(4)`. |
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