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If an AC voltage 100 V is applied between points A and B, then current of 1 A and phase difference between current and voltage will be `Deltaphi=37^(@)` . IF the same voltage is applied between points B and C, then current of 5 A and `Deltaphi =53^(@)` What will be the impedance `(in Omega)` in the chain, if the same voltage is applied between points A and C? Round off to nearest integer. |
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Answer» Correct Answer - `0119` `tanphi=(wL_(1))/R_(1)=3/4` `wL_(1)=3/4R_(1)` `1=100/sqrt(9/16R_(1)^(2)+R_(1)^(2))` `R_(1)=80Omega omegaL_(1)=60Omega` `(wL_(2))/R_(2)=4/3 Rightarrow wL_(2)=4/3R_(2)` `5=100/sqrt(16/9 R_(2)^(2)+R_(2)^(2)) Rightarrow R_(2)=12 Omega, WL_(2)=16Omega` `z=sqrt((wL_(1)+wL_(2))^(2)+(R_(1)+R_(2))^(2)) =119 Omega` |
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