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If an electron enters a space between the plates of a parallel plate capacitor at an angle `theta_(1)` with the plates and leaves at an angle `theta_(2)` to the plates, the ratio of its kinetic energy while entering the capacitor to that while leaving will beA. `(cos^(2)theta_(2))/(cos^(2)theta_(1))`B. `(cos^(2)theta_(1))/(cos^(2)theta_(2))`C. `(sin^(2)theta_(2))/(sin^(2)theta_(1))`D. `(sin^(2)theta_(1))/(sin^(2)theta_(2))` |
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Answer» If `V_(1)` and `V_(2)` be the speeds of electron while entering the capacitor and while leaving it, then `v_(1)costheta_(1)=v_(2)costheta_(2)rArr(v_(1))/(v_(2))=(costheta_(2))/(costheta_(1))` `((K.E.))/((K.E.)_(2))=((costheta_(2))/(costheta_(1)))^(2)` |
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