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If an electron is moving with a velocity `600 ms^(-1)` which is accurate upto 0.005%, then calculate the uncertainty in its position `(h = 6.63 xx 10^(-34)Js, " mass of electron" = 9.1 xx 10^(-31) kg)` |
Answer» Velocity of the electron `= 600 ms^(-1)` Uncertainty in velocity `= (0.005)/(100) xx 600 ms^(-1) = 0.03 ms^(-1) = 3 xx 10^(-2) ms^(-1)` Now `(Delta x) (m Delta v) = (h)/(4pi)` `:. Delta x = (h)/(4pi m Delta v) = (6.63 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14 xx 9.1 xx 10^(-31) kg xx 3 xx 10^(-2) ms^(-1)) = 1.93 xx 10^(-3)m` |
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