1.

If an electron is moving with a velocity `600 ms^(-1)` which is accurate upto 0.005%, then calculate the uncertainty in its position `(h = 6.63 xx 10^(-34)Js, " mass of electron" = 9.1 xx 10^(-31) kg)`

Answer» Velocity of the electron `= 600 ms^(-1)`
Uncertainty in velocity `= (0.005)/(100) xx 600 ms^(-1) = 0.03 ms^(-1) = 3 xx 10^(-2) ms^(-1)`
Now `(Delta x) (m Delta v) = (h)/(4pi)`
`:. Delta x = (h)/(4pi m Delta v) = (6.63 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14 xx 9.1 xx 10^(-31) kg xx 3 xx 10^(-2) ms^(-1)) = 1.93 xx 10^(-3)m`


Discussion

No Comment Found

Related InterviewSolutions