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If an electron is revolving in a circular orbit of radius `0.5A^(@)` with a velocity of `2.2xx10^(6)m//s`. The magnetic dipole moment of the revolving electron isA. `8.8xx10^(-24)Am`B. `8.8xx10^(-23)Am`C. `8.8xx10^(-22)Am`D. `8.8xx10^(21)Am` |
Answer» Correct Answer - 1 `M= i nA ` and `i=(q)/(T)` |
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