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if an electron is revolving in its bohr orbit having bohr radius of `0.529Å`, then the radius of third orbit isA. `4234Å`B. `4496Å`C. `4.761Å`D. `5125nm` |
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Answer» Correct Answer - C As`r_n=n^2a_0`, Here, `a_0=0.529Å` and `n=3` `therefore r_(n=3)=(3)^2a_0=9xx0.529Å=4.761Å` |
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