If an=∑nk=0(loge10)nk!(n−k)! for n≥0 then a0+a1+a2+a3+…… upt – InterviewSolution

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1.	If an=∑nk=0(loge10)nk!(n−k)! for n≥0 then a0+a1+a2+a3+…… upto ∞ is equal to ts (where ‘t’ is a least possible two digit number and ‘s’ an even number). Which of the following is correct?
Answer» If $a_{n} = \sum_{k = 0}^{n} \frac{(l o g_{e} 10)^{n}}{k! (n - k)!}$ for $n \geq 0$ then $a_{0} + a_{1} + a_{2} + a_{3} + \dots \dots$ upto $\infty$ is equal to $t^{s}$ (where ‘t’ is a least possible two digit number and ‘s’ an even number). Which of the following is correct?

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