If An=π/2∫0sin(2n−1)xsinx dx,Bn=π/2∫0(sinnxsinx)2 dx, for n∈ – InterviewSolution

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1.	If An=π/2∫0sin(2n−1)xsinx dx,Bn=π/2∫0(sinnxsinx)2 dx, for n∈N, then
Answer» If $A_{n} = π / 2 \int 0 \frac{sin (2 n - 1) x}{sin x} d x, B_{n} = π / 2 \int 0 {(\frac{sin n x}{sin x})}^{2} d x,$ for $n \in N,$ then

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