If angle between line →r=^i+2^+2^k+λ(4^j−3^k) and XY plane is α, – InterviewSolution

1.	If angle between line →r=^i+2^+2^k+λ(4^j−3^k) and XY plane is α, and angle between the planes x+2y=0 and 2x+y=0 is β, then cos2αsin2β=
Answer» If angle between line $\to r =^i + 2^+ 2^k + λ (4^j - 3^k)$ and $X Y$ plane is $α$ , and angle between the planes $x + 2 y = 0$ and $2 x + y = 0$ is $β$ , then $\frac{{cos}^{2} α}{{sin}^{2} β} =$

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