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If any equilibrium process equation is multiply by any factor n, still there is no change in equilibrium constant explain with example. |
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Answer» Solution :The equilibrium of HI SYNTHESIS at definite temperature is as under. `H_(2(g)) + I_(2(g)) hArr 2HI_((g))`…(Eq.-i) The equilibrium constant `K_c` is as, `K_c=([HI]^2)/([H_2][I_2])=X` ….(Eq.-ii) On MULTIPLYING the [7.9(ii)] HI synthesis equation by n, we GET (Eq.-7.18). `nH_2+nI_2=2n HI`....(Eq.-iii) For this (Eq.-7.18) reaction the equilibrium constant `K.._c` so, `K.._c=([HI]^(2n))/([H_2]^n [I_2^n])=[[HI]^2/([H_2][I_2])]^n=X^n`....(Eq.-iv) Thus , `K_c=[I_2]^n` and `K.._c=X^n` `therefore (K_c)(K.._c)=(X)(X)^n` `therefore K.._c=(K_c)^n`...(Eq.-v) It should be noted that because the equilibrium constants `K_c` and `K.._c` have different numerical values, it is important to SPECIFY the form of the balanced chemical equation when quoting the value of an equilibrium constant. |
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