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If any tangent to the ellipse `(x^2)/(a^@)+(y^2)/(b^2)=1`interceptsequal lengths `l`on theaxes, then find `ldot` |
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Answer» Correct Answer - `sqrt(a^(2)+b^(2))` The equation of tangenet to the given ellipse at point `P(a cos theta, b sin theta)` is `(x)/(a) cos theta+(y)/(b) sin theta=1` The intercepts of line on the ellipse are `a//cos theta and b//sin theta`. Given that `(a)/(costheta)=(b)/(sin theta)l or cos theta=(theta)/(l)and sin theta=(b)/(l)` or `cos^(2)theta+sin^(2)theta=(a^(2))/(l^(2))+(b^(2))/(l^(2))` `or l^(2)=a^(2)+b^(2)` or `l=sqrt(a^(2)+b^(2))` |
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