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If [axxb bxxc c xxa]=lambda[abc]^(2), then lambda is euqual to |
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Answer» Solution :Given,` [ a xx b "" b xx C "" c xx a] = lambda [ "a b c"]^(2)` `LHS = (a xx b ) * [ (b xx c) xx (c xx a ) ]` ` = (a xx b)*[{b*(cxxa)}c-{c*(cxxa)}b]` `=(a xx b) *{["b c a"] c - 0} "" [ because c *(c xx a) = 0] ` `={(a xx b) *c} [ "b c a"]=["a b c"]["b c a"] ` `=[ "a b c"]["a b c"] "" [ because ["b c a"]=["a b c"]]` `=["a b c"]^(2)=RHS` `THEREFORE lambda = 1` |
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