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If [axxb bxxc c xxa]=lambda[abc]^(2), then lambda is euqual to

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Solution :Given,` [ a xx b "" b xx C "" c xx a] = lambda [ "a b c"]^(2)`
`LHS = (a xx b ) * [ (b xx c) xx (c xx a ) ]`
` = (a xx b)*[{b*(cxxa)}c-{c*(cxxa)}b]`
`=(a xx b) *{["b c a"] c - 0} "" [ because c *(c xx a) = 0] `
`={(a xx b) *c} [ "b c a"]=["a b c"]["b c a"] `
`=[ "a b c"]["a b c"] "" [ because ["b c a"]=["a b c"]]`
`=["a b c"]^(2)=RHS`
`THEREFORE lambda = 1`


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