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If b+ic=(1+a)z and a2+b2+c2=1, where a,b,c∈R, then 1+iz1−iz=a+ibk where k is equal to |
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Answer» If b+ic=(1+a)z and a2+b2+c2=1, where a,b,c∈R, then 1+iz1−iz=a+ibk where k is equal to |
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