1.

If |bar(a)|=1 and bar(a)xx bar(b)=(1,2,3) then bar(a)xx[bar(a)xx(bar(a)xx bar(b))] = ……. .

Answer»

(1, 2, 3)
`(-1, -2, -3)`
`(0, 0, 0)`
(1, 0, 0)

ANSWER :B


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