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If `[(bara, barb, barc)]=2` and `(veca.vecb)=2, (vecc.veca)=5` then, `veca` is equal to `xbarb+ybarc+z(barbxxbarc)` (where `barb` & `barc` are two non -coplanar orthogonal unit vectors then`(x+y-z)=?` |
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Answer» Correct Answer - 5 Let `bara=xbarb+ybarc+z(barbxxbarc)` `impliesbara.barb=x(barb.bar)+y(barb.barc)=2` `x+y(barb.barc)=2`…….(1) `bara.barc=0+yxx1=5` `y=5` `bara.(barbxxbarc)=0+0+z|barbxxbarc|^(2)` `z=2` |
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