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If barb and barc are two non-collinear vectors, then number of solution (x,y) in x,y in [0,10], satisfying the equation bara.[barb+barc] = 5 and bara xx (barb xx barc) = (x^2 -2x+7) barb+(siny)barc is : |
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Answer» ONE `impliesbara-barc =x^2 - 2x + 7, bara .""barb=-siny` `bara.(barb + barc) = 5` `impliesx^2 - 2x + 7 -siny=5` `implies (x-1)^2 + 1 = sin y` `x=1, y=(4n+1) (pi)/(2) = (pi)/(2),(5pi)/(2)` |
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