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If \( \begin{bmatrix}1& 0 & 0 \\[0.3em]0 & 1 & 0\\[0.3em]0 & 0 & 1\end{bmatrix}\) \( \begin{bmatrix}a \\[0.3em]b \\[0.3em]c\end{bmatrix}\) = \( \begin{bmatrix}2 \\[0.3em]1 \\[0.3em]-3\end{bmatrix}\) then the value of a + b + c is(A) 6(B) 3(C) 2(D) 0 |
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Answer» Correct option is: (D) 0 |
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